Headphone Amplifier Power
Calculate the amplifier output power, voltage, and current required to drive headphones to a target SPL.
Formula
P = 10^((SPL − S)/10) mW, V = √(P × Z)
How It Works
Worked Example
Headphone: 300 Ω impedance, 100 dB/mW sensitivity. Target SPL: 110 dB. Required power: P_mW = 10^((110 − 100) / 10) = 10^1.0 = 10 mW P_W = 10 / 1000 = 0.010 W Required RMS voltage: V_rms = √(0.010 × 300) = √3.0 = 1.73 V Required current: I_mA = (1.73 / 300) × 1000 = 5.77 mA A typical smartphone output maxes at ~1.0–1.5 V RMS, so it can drive these headphones to about 107–108 dB — adequate but with minimal headroom. A dedicated amplifier providing at least 2 V RMS into 300 Ω is recommended for peaks.
Practical Tips
- ✓For most home use at comfortable volume (~85 dB SPL), power requirements are tiny (under 1 mW). Focus amplifier selection on achieving low noise floor and adequate voltage swing rather than maximum power.
- ✓Rule of thumb: 100× the required power to reach target SPL gives you 20 dB of headroom — enough for transient peaks without clipping. If you need 1 mW for 90 dB, a 100 mW amplifier gives comfortable headroom.
- ✓Planar-magnetic headphones (e.g., HiFiMAN, Audeze) are typically 20–60 Ω but have low sensitivity (90–95 dB/mW), requiring both current and voltage — they benefit most from dedicated headphone amplifiers.
Common Mistakes
- ✗Mixing up sensitivity units — headphone datasheets may quote sensitivity as dB/mW or dB/V (at 1 V RMS). Converting: if sensitivity is given as dB/V, then dB/mW = dB/V − 10·log₁₀(1000/Z). For 300 Ω: dB/mW = dB/V + 10·log₁₀(Z/1000) = dB/V − 5.2 dB.
- ✗Targeting SPL that risks hearing damage — 110 dB SPL at the ear is safe for only ~1 minute per NIOSH guidelines. 85 dB for 8 hours is the recommended limit. Use the calculator to ensure your amplifier can reach 100–105 dB with headroom, not to maximise output.
- ✗Ignoring output impedance of the amplifier — a high-output-impedance amp (>10 Ω) forms a voltage divider with the headphone, reducing power delivery and altering the frequency response because headphone impedance is not flat.
Frequently Asked Questions
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