Power Amplifier Efficiency Calculator (PAE & Drain Efficiency)
Calculate RF power amplifier PAE, drain efficiency, gain, and heat dissipation from Pout, Pin, and DC bias. Essential for PA design. Free, instant results.
Formula
How It Works
Power amplifier efficiency measures DC-to-RF power conversion — wireless infrastructure engineers, transmitter designers, and battery-powered device developers use efficiency metrics to minimize heat dissipation and maximize operating time. Drain efficiency eta_D = P_RF_out / P_DC ranges from 25% (Class A) to 90% (Class E/F) depending on amplifier topology, per Cripps' 'RF Power Amplifiers for Wireless Communications' (2nd ed.).
Power-added efficiency PAE = (P_RF_out - P_RF_in) / P_DC accounts for driver power, which becomes significant in high-gain systems. For a 20 W amplifier with 15 dB gain consuming 40 W DC: eta_D = 20/40 = 50%, but P_RF_in = 20/31.6 = 0.63 W, so PAE = (20-0.63)/40 = 48.4%. PAE converges to drain efficiency at high gain.
Class definitions per Krauss's 'Solid State Radio Engineering': Class A (conduction angle 360 degrees, theoretical max 50%) operates linearly with constant bias current. Class AB (180-360 degrees, 50-78%) reduces quiescent current for efficiency. Class B (180 degrees, 78.5% max) eliminates quiescent current. Class C (< 180 degrees, up to 90%) is highly efficient but nonlinear. Class D/E/F switching amplifiers achieve 90%+ efficiency through zero-voltage or zero-current switching. Modern 5G base stations use Doherty architecture achieving 50-55% PAE at 6 dB output back-off.
Worked Example
Design thermal management for a 100 W cellular base station power amplifier with 45% drain efficiency and 15 dB gain.
Efficiency analysis:
- DC power consumption: P_DC = P_RF_out / eta_D = 100 / 0.45 = 222 W
- Input RF power: P_RF_in = 100 W / 10^(15/10) = 100/31.6 = 3.16 W
- Power-added efficiency: PAE = (100 - 3.16) / 222 = 43.6%
- Heat dissipation: P_heat = P_DC - P_RF_out = 222 - 100 = 122 W
- Junction-to-case thermal resistance: Rth_jc = 0.5 C/W (typical LDMOS)
- Maximum junction temperature: T_j_max = 175 C (GaN) or 200 C (LDMOS)
- Ambient temperature: T_amb = 55 C (outdoor cabinet)
- Maximum case-to-ambient thermal resistance:
- Heatsink requirement: 0.48 C/W with forced-air cooling
Efficiency improvement options:
- Doherty PA: 52% efficiency at 8 dB OBO — saves 31 W at same output
- Envelope tracking: 55% average efficiency — saves 40 W
- Digital predistortion (DPD) allows operation closer to saturation: +3% efficiency
fan-cooled heatsink or cold plate with liquid cooling
Efficiency improvement options:
- Doherty PA: 52% efficiency at 8 dB OBO — saves 31 W at same output
- Envelope tracking: 55% average efficiency — saves 40 W
- Digital predistortion (DPD) allows operation closer to saturation: +3% efficiency
Practical Tips
- ✓Specify PAE at rated output AND at 8-10 dB back-off for linear applications (cellular, WiFi) — saturated efficiency is misleading for signals with high PAPR
- ✓Budget 30-50% efficiency for linear PAs in production systems; 60-70% for constant-envelope (FM, FSK) or switching amplifiers; claims above 70% linear efficiency require advanced techniques (Doherty, ET, outphasing)
- ✓For battery applications, consider average efficiency over the power probability distribution — a PA with 50% peak efficiency but 20% efficiency at typical output levels wastes more power than 40%/35% design
Common Mistakes
- ✗Measuring efficiency only at saturation — practical signals (OFDM, LTE) have 8-12 dB peak-to-average ratio (PAPR); efficiency at 8 dB back-off is 3-4x worse than saturated efficiency. Always specify efficiency at operating back-off point
- ✗Neglecting thermal runaway risk — GaAs and GaN devices have positive temperature coefficient of drain current; inadequate heatsinking causes thermal runaway and catastrophic failure within seconds at high power
- ✗Ignoring driver stage power — a 10 W driver for a 100 W PA operating at 10% efficiency consumes 100 W DC, equaling the final stage dissipation; include all stages in system efficiency calculation
- ✗Using wrong supply voltage for efficiency comparison — efficiency increases with lower supply voltage due to reduced I^2*R_on losses; compare amplifiers at same supply voltage and output power
Frequently Asked Questions
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