Power Supply Ripple Filter
Calculate LC filter attenuation, resonant frequency, and output ripple voltage. Design power supply EMC filters for ripple rejection.
Formula
How It Works
The power supply ripple filter calculator determines LC component values and attenuation for post-regulator filtering — essential for sensitive analog circuits, precision ADCs, and RF systems. Power integrity engineers, mixed-signal designers, and EMC specialists use this tool to achieve <1 mV ripple from switching power supplies. According to TI application note SLVA630, a single-stage LC filter provides -40 dB/decade attenuation above its corner frequency f0 = 1/(2π√LC), with the relationship f0 = fsw/10^(A/40) determining required corner frequency for target attenuation A (dB). For a 500 kHz SMPS requiring 40 dB attenuation, f0 = 50 kHz. Per Analog Devices MT-101, output ripple comprises capacitive (ΔVc = ΔIL/(8×fsw×C)) and ESR (ΔVesr = ΔIL × ESR) components — modern MLCC ceramics with <10 mΩ ESR make ESR contribution negligible versus capacitive ripple. The filter's characteristic impedance Z0 = √(L/C) should match load impedance for optimal damping; mismatched impedance causes resonant peaking at f0 that can amplify noise by 10-20 dB. Critical consideration: MLCC capacitors lose 50-80% capacitance at DC bias — always use derated values in filter calculations.
Worked Example
Design a ripple filter to reduce 500 kHz SMPS noise from 50 mV to <1 mV for a 16-bit ADC reference supply. Requirements: 3.3 V at 100 mA, Z_load ≈ 33 Ω. Step 1: Calculate required attenuation — A = 20×log10(50/1) = 34 dB. Use 40 dB for margin. Step 2: Determine corner frequency — f0 = 500k/10^(40/40) = 50 kHz. Step 3: Calculate LC product — LC = 1/(2π×50k)² = 1.01×10^-9 s². Step 4: Match load impedance — For Z0 = 33 Ω: L/C = 1089, so L = √(1089 × 1.01×10^-9) = 33 µH. C = LC/L = 1.01×10^-9/33×10^-6 = 30.6 nF. Step 5: Select components — Use 33 µH inductor (Murata LQH32CN330K, 0.15 Ω DCR) and 47 nF C0G ceramic (no DC bias derating). Step 6: Add damping — Insert 10 Ω in series with 1 µF across main capacitor to damp resonance. Step 7: Verify — Filter attenuation at 500 kHz: 40 + 40×log10(500k/50k) = 40 + 40 = 80 dB. Residual ripple = 50 mV / 10^(80/20) = 5 µV. Output noise dominated by regulator and component noise, not ripple.
Practical Tips
- ✓Per TI precision ADC design guide, use ferrite beads (600 Ω at 100 MHz type) instead of inductors for frequencies above 10 MHz — ferrite's resistive impedance provides natural damping without resonance issues
- ✓Cascade two LC stages for >60 dB attenuation — single stage limited by capacitor self-resonance (typically 1-10 MHz for MLCC); second stage handles frequencies above first stage's effectiveness
- ✓Add 10-100 nF C0G capacitor directly at ADC Vref pin — provides final high-frequency bypass that the main filter's inductance prevents from being effective
Common Mistakes
- ✗Using X5R/X7R capacitors without DC bias derating — a 10 µF/6.3V X5R at 3.3 V DC retains only 5-6 µF effective capacitance, halving filter attenuation; use C0G/NP0 for filter applications or 2× rated voltage ceramics
- ✗Ignoring resonant peaking — undamped LC filter amplifies noise 10-20 dB at f0; always add damping resistor (Rd = 0.5×Z0 typical) in series with a larger bypass capacitor
- ✗Placing filter far from load — parasitic inductance (10 nH/cm) between filter and load allows high-frequency noise to bypass filter; keep filter-to-load distance <5 mm
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