BLDC Thermal Derating Calculator
Calculate BLDC motor winding temperature, thermal margin, derated current, and time to thermal limit. Supports insulation classes B, F, and H.
Formula
Reference: IEC 60034-1 — Rotating electrical machines; NEMA MG-1
How It Works
This calculator models BLDC motor temperature rise using a thermal resistance network to verify that winding temperatures stay within insulation class limits. Motor designers, drone builders, and industrial integrators use it to determine continuous current ratings and required cooling for their operating environment.
The steady-state thermal model follows an electrical analogy: heat flow (watts) through thermal resistance (C/W) produces temperature difference (C). Per Mellor's thermal model (IEE Proc. 1991), the primary path is winding -> stator iron -> case -> ambient, with , where is winding-to-case and is case-to-ambient thermal resistance.
Insulation class defines the maximum allowable winding temperature per IEC 60085: Class B (130C), Class F (155C), and Class H (180C). Most hobby BLDC motors use Class B or F enamel wire. Exceeding the rating by 10C halves insulation life per the Arrhenius rule -- thermal margin is not optional.
Copper resistance increases with temperature: where /C for copper. This creates positive thermal feedback: hotter windings have higher resistance, causing more loss, which further raises temperature. The equilibrium temperature must be solved iteratively or via the closed-form: .
The first-order thermal time constant (where is thermal capacitance in J/C) determines how quickly the motor heats. Small drone motors ( = 10-30 s) reach 63% of final temperature in under 30 seconds. This means burst current ratings are only safe for durations well below .
Worked Example
Verifying a 4008-380Kv motor can handle 15A continuous in 40C ambient. Specs: = 0.120 ohm (wye, at 25C), = 0.8 A at 22.2V (6S), Class F insulation (155C max), = 1.5 C/W, = 8.0 C/W (natural convection).
Step 1 -- Calculate losses at 25C resistance: = = 81.0 W = 22.2 x 0.8 = 17.8 W (iron + mechanical) = 81.0 + 17.8 = 98.8 W
Step 2 -- Estimate winding temperature (first pass): = 1.5 + 8.0 = 9.5 C/W = 98.8 x 9.5 = 938.6 C -- clearly too hot!
Step 3 -- This motor cannot run 15A with natural convection. Add prop wash cooling: With 12-inch prop airflow: drops to 2.0 C/W (forced convection) = 1.5 + 2.0 = 3.5 C/W = 98.8 x 3.5 = 345.8 C -- still exceeds limit
Step 4 -- Find maximum safe continuous current: Thermal budget: = 155 - 40 = 115 C Accounting for hot resistance: = = 115 / 3.5 = 32.9 W Subtract no-load loss: = 32.9 - 17.8 = 15.1 W = = 6.5 A continuous With hot resistance at 155C: = 0.120 x (1 + 0.00393 x 130) = 0.181 ohm Corrected: = = 5.3 A
Result: Maximum continuous current is 5.3A (not 15A) with forced prop cooling in 40C ambient. The motor can handle 15A only for short bursts -- approximately 15 seconds assuming = 25 s thermal time constant.
Practical Tips
- ✓Estimate case-to-ambient thermal resistance as 8-15 C/W for natural convection (bench testing) and 1.5-3 C/W for forced airflow from a propeller or fan -- prop wash reduces thermal resistance by 3-5x, so bench test results are much worse than in-flight performance
- ✓Measure winding temperature indirectly via resistance: run the motor under load, stop it, and immediately measure phase resistance -- back-calculate temperature as ; this is more accurate than external thermocouples which only read case temperature
- ✓Apply a 15-20C thermal margin below the insulation class limit to account for hot spots inside the winding that are 10-20C hotter than the average winding temperature -- if Class F is rated 155C, design for 135C maximum average
Common Mistakes
- ✗Using cold (25C) winding resistance for continuous thermal calculations: At 130C temperature rise, copper resistance is 51% higher than at 25C, meaning actual copper loss is 51% more than calculated -- this positive feedback loop is the most common cause of unexpected motor burnout
- ✗Forgetting to derate for ambient temperature: A motor rated for 15A at 25C ambient can only handle ~12A at 45C ambient because the thermal budget shrinks from 130C to 110C -- always subtract actual ambient from the insulation class limit to get the true allowable temperature rise
- ✗Assuming peak current rating equals continuous rating: A motor rated for 30A peak (10 seconds) may only handle 8-12A continuous -- thermal time constants of 15-30 seconds mean the motor reaches dangerous temperatures within 2-3 time constants (30-90 seconds) at peak current
Frequently Asked Questions
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