Smith Chart Calculator
Interactive Smith Chart for impedance matching and RF network analysis. Enter load impedance to visualize reflection coefficient, VSWR circle, and normalized impedance.
Presets
Inputs
Positive = inductive, negative = capacitive
Results
Smith Chart
Formula
Reference: Pozar, Microwave Engineering 4th Ed., Chapter 2
How It Works
The Smith Chart is a graphical tool invented by Phillip H. Smith at Bell Labs in 1939. It provides a way to visualize complex impedance and reflection coefficient simultaneously on a single normalized diagram, making it indispensable for transmission line analysis, impedance matching, and RF amplifier design. The chart is plotted in the complex reflection coefficient (Γ) plane, where the horizontal axis represents the real part of Γ and the vertical axis represents the imaginary part. The outer boundary circle has a radius of |Γ| = 1, representing total reflection (open circuit, short circuit, or purely reactive loads). The center of the chart corresponds to Γ = 0, the condition of perfect impedance match. Overlaid on the Γ-plane are two families of orthogonal circles: 1. Constant-resistance circles: Each circle in this family represents all impedances with the same normalized resistance r = R/Z₀. The circle for r has its center at (r/(r+1), 0) in the Γ-plane and radius 1/(r+1). All circles are tangent to the right-hand edge of the chart (Γ = +1, open circuit). The r = 1 circle passes through the center of the chart. 2. Constant-reactance arcs: Each arc represents all impedances with the same normalized reactance x = X/Z₀. The arc for x has its center at (1, 1/x) in the Γ-plane and radius |1/x|. Arcs in the upper half of the chart correspond to inductive (positive) reactance; arcs in the lower half correspond to capacitive (negative) reactance. To use the chart, normalize the load impedance: z = Z/Z₀ = r + jx. Locate the point at the intersection of the r-circle and x-arc to find Γ graphically. The magnitude |Γ| equals the distance from the chart center to that point, and the VSWR equals (1 + |Γ|)/(1 − |Γ|). Traveling along a lossless transmission line moves the impedance point along a constant-|Γ| (constant-VSWR) circle, clockwise toward the generator, completing one full revolution every half wavelength.
Worked Example
Problem: Find the reflection coefficient, VSWR, and return loss for a load Z = 25 + j30 Ω connected to a 50 Ω transmission line. Suggest a simple L-network impedance match. Step 1 — Normalize the impedance: z = Z/Z₀ = (25 + j30)/50 = 0.5 + j0.6 Step 2 — Compute the reflection coefficient: Γ = (z − 1)/(z + 1) Numerator: (0.5 − 1) + j0.6 = −0.5 + j0.6 Denominator: (0.5 + 1) + j0.6 = 1.5 + j0.6 |Denominator|² = 1.5² + 0.6² = 2.25 + 0.36 = 2.61 Γ_real = (−0.5×1.5 + 0.6×0.6)/2.61 = (−0.75 + 0.36)/2.61 = −0.39/2.61 ≈ −0.1494 Γ_imag = (0.6×1.5 − (−0.5)×0.6)/2.61 = (0.9 + 0.3)/2.61 = 1.2/2.61 ≈ 0.4598 |Γ| = √(0.1494² + 0.4598²) ≈ √(0.02232 + 0.21142) ≈ √0.23374 ≈ 0.4835 Step 3 — VSWR: VSWR = (1 + 0.4835)/(1 − 0.4835) = 1.4835/0.5165 ≈ 2.87:1 Step 4 — Return Loss: RL = −20 log₁₀(0.4835) ≈ −20 × (−0.3156) ≈ 6.31 dB This indicates a moderately poor match — about 23% of power is reflected. Step 5 — Mismatch Loss: ML = −10 log₁₀(1 − 0.4835²) = −10 log₁₀(1 − 0.2338) = −10 log₁₀(0.7662) ≈ 1.16 dB Step 6 — L-network matching strategy: The load z = 0.5 + j0.6 lies inside the r = 1 circle. Strategy A (shunt-C then series-L): First, add a shunt capacitor to cancel the inductive reactance and bring z to 0.5 + j0. At 1 GHz, C_shunt ≈ (0.6 × 50) / (2π × 1e9 × 50²) — use the Smith Chart to read the exact susceptance. Then add a series inductor to move from z = 0.5 to z = 1 (the r = 1 circle intersects real axis only at z=1). Alternatively, use a quarter-wave transformer with Z_transformer = √(50 × 25) = 35.4 Ω for the resistive part only (after cancelling reactance).
Practical Tips
- ✓Use the VSWR circle for matching network design: draw the circle through your load point and identify where it crosses the r = 1 circle. That crossing point tells you exactly what series reactance to add to reach a perfect match.
- ✓Quarter-wave transformer design: if your normalized load is purely resistive (r ≠ 1, x = 0), the impedance point lies on the real axis. A quarter-wave transformer of impedance Z_T = √(Z₀ × R_load) rotates it exactly 180° to reach the matched center.
- ✓Read admittance from the same chart: rotate any impedance point 180° around the chart center to obtain the normalized admittance y = 1/z. This lets you handle shunt elements without converting manually.
- ✓Combine series and shunt moves for L-networks: series elements move along constant-r circles; shunt elements move along constant-g (conductance) circles. An L-network trace on the Smith Chart shows two perpendicular arc segments meeting at the center.
- ✓Check stability on transistor amplifiers: plot the input and output stability circles on the Smith Chart to identify the region of source/load impedances that keep the amplifier unconditionally stable.
- ✓Use the chart to verify VNA calibration: a known short (Γ = −1), open (Γ = +1), and load (Γ = 0) should fall exactly at the left edge, right edge, and center of the Smith Chart respectively. Deviations indicate calibration error.
Common Mistakes
- ✗Forgetting to normalize: The Smith Chart only works with normalized impedance z = Z/Z₀. Plotting raw ohm values directly produces incorrect results. Always divide R and X by Z₀ before locating the point.
- ✗Confusing inductive and capacitive halves: The upper half of the Smith Chart (positive imaginary axis) represents inductive (positive) reactance. The lower half represents capacitive (negative) reactance. This is the opposite of some textbook phasor conventions that plot inductive loads below the axis.
- ✗Using the wrong reference impedance: If your system is 75 Ω (cable TV) but you normalize to 50 Ω, every point will be mislocated. Always use the system characteristic impedance Z₀ as the normalizing value.
- ✗Ignoring frequency dependence: A Smith Chart point is only valid at a single frequency. Impedance is frequency-dependent, so a matched condition at 2.4 GHz may be mismatched at 5 GHz. Always sweep frequency with a VNA to characterize over a band.
- ✗Treating VSWR circle movement as linear distance: Moving along the VSWR circle corresponds to electrical length, not physical length. One full revolution = λ/2 electrical length. Physical length depends on the velocity factor of the transmission line medium.
- ✗Confusing Smith Chart admittance and impedance: The Smith Chart can be used for admittance (Y = 1/Z) by rotating the chart 180°. Shunt elements move along constant-conductance circles, not constant-resistance circles. Mixing the two conventions leads to incorrect matching designs.
Frequently Asked Questions
What does the center of the Smith Chart represent?
The center of the Smith Chart corresponds to Γ = 0, meaning there is no reflected wave and the load impedance equals the reference impedance Z₀. This is the condition of perfect impedance match. For a 50 Ω system, the center represents Z = 50 + j0 Ω.
Why does a lossless transmission line trace a circle on the Smith Chart?
A lossless transmission line transforms impedance as Z_in = Z₀ × (Z_L + jZ₀tan(βl)) / (Z₀ + jZ_Ltan(βl)). In the Γ-plane, this transformation is a rotation about the origin by an angle −2βl. Since rotation at constant radius is a circle, any lossless line traces a constant-|Γ| (constant-VSWR) circle. One full circle corresponds to λ/2 of electrical length.
How do I match an inductive load using the Smith Chart?
Plot the normalized load impedance z = r + jx on the chart. If x > 0 (inductive), you can: (1) add a series capacitor to move counterclockwise along the constant-r circle until you reach the real axis, then use a quarter-wave transformer; or (2) use the L-network approach by first adding a shunt element to reach the r = 1 circle, then adding a series element to reach the center. The exact element values are read from the chart's reactance and susceptance scales.
What is the difference between return loss and mismatch loss?
Return loss (RL = −20 log|Γ| dB) measures the power reflected back toward the source relative to the incident power. A higher number means less reflection (20 dB return loss means 1% reflected power). Mismatch loss (ML = −10 log(1−|Γ|²) dB) measures the power that fails to reach the load — it equals the insertion loss caused by the impedance mismatch alone. At VSWR 2:1, return loss ≈ 9.54 dB but mismatch loss is only ≈ 0.51 dB, meaning 89% of the power still reaches the load.
When should I use a Smith Chart instead of just calculating Γ numerically?
Smith Charts are most valuable when designing multi-element matching networks, analyzing transmission-line transformations, or performing simultaneous noise and gain optimization on transistor amplifiers. The graphical nature lets you see the trade-offs intuitively — for example, how far a stub must move an impedance toward the match point, or whether a small change in component value significantly improves the match. For simple single-frequency calculations, numerical computation is faster; for design insight and iteration, the Smith Chart is unmatched.
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