Buck Converter Design Calculator
Design a synchronous buck converter: calculate duty cycle, inductor, output and input capacitors, peak current, and ripple. Free, instant results.
Formula
Reference: Erickson & Maksimovic, "Fundamentals of Power Electronics" 3rd ed.
How It Works
The buck converter calculator computes duty cycle, inductor value, and capacitor requirements for step-down DC-DC conversion — essential for point-of-load regulators, battery chargers, and embedded power supplies. Power electronics engineers, hardware designers, and SMPS developers use this tool to achieve 90-98% efficiency in voltage reduction. According to Erickson & Maksimovic's 'Fundamentals of Power Electronics' (3rd ed.), synchronous buck converters reach 97% efficiency at 500 kHz switching frequency with properly selected GaN FETs exhibiting 5 mΩ Rds(on). The duty cycle D = Vout/Vin determines the voltage conversion ratio in continuous conduction mode (CCM). Inductor selection follows L = Vout(1-D)/(fsw × ΔIL), where 20-40% peak-to-peak ripple current is standard per TI application note SLVA477. Output capacitor requirements depend on ripple voltage target: Cout = ΔIL/(8 × fsw × ΔVout) for ceramic capacitors, with ESR-dominated ripple requiring ESR < ΔVout/ΔIL. Modern integrated converters (TI TPS62840, 60 nA quiescent) enable 95% efficiency even at 1 µA load current.
Worked Example
Design a 12 V to 3.3 V buck converter for a Raspberry Pi supply at 3 A maximum load. Target specifications: <30 mV output ripple, >92% efficiency, 500 kHz switching frequency. Step 1: Calculate duty cycle — D = 3.3/12 = 0.275 (27.5%). Step 2: Select inductor for 30% ripple — ΔIL = 0.3 × 3 A = 0.9 A. L = 3.3 × (1-0.275)/(500k × 0.9) = 5.3 µH. Use standard 4.7 µH (Würth 744373680047) with 8.5 A saturation current. Step 3: Calculate output capacitance — Cout = 0.9/(8 × 500k × 0.03) = 7.5 µF minimum. Use 3 × 22 µF/10V X5R ceramics (effective 45 µF after DC bias derating). Step 4: Select controller — TI TPS54360 (60 V input, 3.5 A output) with integrated compensation. Step 5: Verify efficiency — Estimated: conduction loss = 3² × 0.07Ω = 0.63 W, switching loss ≈ 0.3 W. Total loss ≈ 0.93 W. Efficiency = 9.9 W/(9.9 + 0.93) = 91.4%.
Practical Tips
- ✓Per TI's 'Power Supply Design Seminar', use ceramic capacitors with X5R or X7R dielectric — Y5V capacitors lose 80% capacitance at DC bias and exhibit ±22% tolerance
- ✓Implement spread-spectrum frequency modulation (SSFM) to reduce EMI peaks by 10-15 dB — TI TPS65281 varies switching frequency ±6% to spread harmonics
- ✓Place input and output capacitors within 5 mm of the IC pins to minimize parasitic inductance — 10 mm trace adds 10 nH, causing 500 mV voltage spikes at 50 A/µs di/dt
Common Mistakes
- ✗Neglecting inductor saturation current — a 10 µH inductor rated for 2 A saturates at 3 A peak (DC + ripple), losing 80% of inductance and causing output voltage collapse
- ✗Using electrolytic capacitors at high frequency — aluminum electrolytics have 100-500 mΩ ESR at 500 kHz, causing 90-450 mV ripple versus <10 mV with MLCC ceramics
- ✗Ignoring input capacitor requirements — input current is pulsed at D × Iload; inadequate input capacitance causes 30-50% higher input ripple, failing EMI requirements
Frequently Asked Questions
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